What is the alcohol content of 1.25 oz of 43% whiskey (86 proof)?

Prepare for the Alcoholic Beverage Control (ABC) Permit Exam with questions and explanations. Boost your knowledge and confidence to pass the exam successfully!

To determine the alcohol content of a specific volume of whiskey, you can use the formula for calculating the volume of alcohol. The alcohol content can be calculated using the volume of the beverage and its alcohol by volume (ABV) percentage.

In this case, you have 1.25 ounces of whiskey with an ABV of 43%. To find the alcohol content in ounces, you multiply the total volume of the whiskey by the ABV expressed as a decimal:

1.25 oz x 0.43 = 0.5375 oz.

When rounded to two decimal places, this results in 0.54 oz of alcohol. Therefore, the correct choice accurately reflects the volume of pure alcohol present in the 1.25 oz of 43% whiskey.

Understanding how to perform this calculation is essential for anyone involved in the sale and distribution of alcoholic beverages, as it helps in making informed decisions regarding alcohol content in drinks served or sold.

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